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Position, Distance, and Displacement 

 Position and Displacement

Students will learn the meaning of an object's position, the difference between distance and displacement and some basic graphing of position vs. time.

Key Equations

\text{Symbols}\begin{cases}\Delta \text{(anything)} & \text{Final value - initial value}\\\text{anything}_0 & \text{Value at time 0}\end{cases}

\text{Scalors}\begin{cases}t & \text{Time in seconds, s}\\d = |{\Delta x_1}| + |{\Delta x_2}| & \text{Distance (in meters, m}\text{)}\\v = |{v}| & \text{Speed (in meters per second,}\ \text{m}/\text{s}\text{)}\end{cases}

\text{Vectors}\begin{cases}x = x(t) & \text{Position} \\\Delta x = x_f-x_i  & \text{Displacement}\\\end{cases}

When beginning a one dimensional problem, define a positive direction. The other direction is then taken to be negative. Traditionally, "positive" is taken to mean "to the right"; however, any definition of direction used consistently throughout the problem will yield the right answer.

Position 

Displacement 

Distance

 


Guidance
Position is the location of the object (whether it's a person, a ball or a particle) at a given moment in time. Displacement is the difference in the object's position from one time to another. Distance is the total amount the object has traveled in a certain period of time. Displacement is a vector quantity (direction matters), where as distance is a scalar (only the amount matters). Distance and displacement are the same in the case where the object travels in a straight line and always moving in the same direction.

 

Example 1

Problem: An indecisive car goes 120 m North, then 30 m south then 60m North. What is the car's distance and displacement?

Solution:

Distance is the total amount traveled. Thus distance = 120 + 30 + 60 m = 210 m

Displacement is the amount displaced from the starting position. Thus displacement = 120 - 30 + 60 m = 150 m.

Example 2

Problem: An 8^{\text{th}} grader is timed to run 24 feet in 12 seconds, what is her speed in meters per second?

Solution:

D & = vt\\24 \ ft & = v(12 \ s)\\ v & = 24 \ ft/12 \ s = 2 \ ft/s\\v & = 2 \ ft/s \ast (1 m/3.28 \ ft) = 0.61 \ m/s